X^2-57x+540=0

Solution for X^2-57x+540=0 equation:

X^2-57X+540=0

a = 1; b = -57; c = +540;
Δ = b2-4ac
Δ = -572-4·1·540
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-57)-33}{2*1}=\frac{24}{2}
=12
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-57)+33}{2*1}=\frac{90}{2}
=45
$